C#创建及获取.csv文件

    bool Filebool = FileUtil.OutPutCsvFile(DATATABLE表, "A:\XXX.csv", false, false);
    
    
      
    

    string csvDirectory="A:\ ";
    DirectoryInfo dicsv = new DirectoryInfo(csvDirectory);
    FileInfo[] fiscsv = dicsv.GetFiles( "XXX"+"*.csv");
    	DataTable dt = FileUtil.OpenCSVFile2DataTable(fiscsv[0].FullName, "", true);
    
    
      
      
      
      
    

    using System;
    using System.Collections.Generic;
    using System.Text;
    using System.IO;
    using System.Data.OleDb;