齿轮动力学方程
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动力学方程的建立过程
%% Function 动力学方程推导 练习
clc;clear;
%% %%%%%%%%%%%%%%%%%%%%%%参数定义及赋值%%%%%%%%%%%%%%%%%%%%%%%%%%%%
syms Mp Mq Ip Iq rp rq
syms thita_p thita_q dthita_p dthita_q deta ddeta de e t Tp Tq km cm
%% %%%%%%%%%%%%%%%%%%%%%%参数定义及赋值%%%%%%%%%%%%%%%%%%%%%%%%%%%%
dpt=[thita_p;thita_q]; %振动位移
%% 方程推导
e=0.02*sin(t)+cos(1+0.5*t);
de=diff(e);
deta=rp*thita_p-rq*thita_q+e;
ddeta=rp*dthita_p-rq*dthita_q+de;
T=1/2*(Ip*dthita_p^2+Iq*dthita_q^2);
U=1/2*(km*deta^2);
R=1/2*(cm*ddeta^2);
L=T-U;
dp(1,1)=Ip\(Tp+diff(L,thita_p)-diff(
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